CAPE Pure Mathematics Unit 1 · May/June 2011 · Paper 1 · Question Q32

Given that \lim_{x \to 0} \frac{\sin x}{x} = 1, where x is measured in radians, then \lim_{x \to 0} \frac{\sin 3x}{2x} is

1. (A)\sin\frac{3}{2}
2. (B)\frac{\sin 3x}{2x}
3. (C)\frac{2}{3}
4. (D)\frac{3}{2}