CAPE Pure Mathematics Unit 2 · May/June 2013 · Paper 2 · Question 6(b)(i)b)
Hence, obtain the complementary function (CF), the general solution of y'' + 2y' + 5y = 0.
The mark scheme is shown once you've answered.
Practise this questionHence, obtain the complementary function (CF), the general solution of y'' + 2y' + 5y = 0.
The mark scheme is shown once you've answered.
Practise this question\cos x \frac{dy}{dx} + y\sin x = 2x\cos^2 x.[7 marks]y = \frac{15\sqrt{2}\pi^2}{32} when x = \frac{\pi}{4}, determine the constant of the integration.[5 marks]y'' + 2y' + 5y = 4\sin 2t is y = CF + PI, where CF is the complementary function and PI is a…[2 marks]PI) is u_p(t) = A\cos 2t + B\sin 2t, show that A = -\frac{16}{17} and B = \frac{4}{17}.[3 marks]y(0) = 0.04 and y'(0) = 0, obtain the general solution of the differential equation.[5 marks]More practice: the rest of this paper · more Differential Equations and Modeling questions · all CAPE Pure Mathematics Unit 2 past papers